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使用Python爬虫库BeautifulSoup遍历文档树并对标签进行操作详解

时间：2020-01-27来源：系统城作者：电脑系统城

下面就是使用Python爬虫库BeautifulSoup对文档树进行遍历并对标签进行操作的实例，都是最基础的内容

html_doc = """
<html><head><title>The Dormouse's story</title></head>
The Dormouse's story
Once upon a time there were three little sisters; and their names were
<a href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" class="sister" id="link1">Elsie</a>,
<a href="http://example.com/lacie" rel="external nofollow" rel="external nofollow"rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow"class="sister" id="link2">Lacie</a> and
<a href="http://example.com/tillie" rel="external nofollow" rel="external nofollow"rel="external nofollow" rel="external nofollow" class="sister" id="link3">Tillie</a>;
and they lived at the bottom of a well.
...
"""
from bs4 import BeautifulSoup
soup = BeautifulSoup(html_doc,'lxml')

一、子节点

一个Tag可能包含多个字符串或者其他Tag，这些都是这个Tag的子节点.BeautifulSoup提供了许多操作和遍历子结点的属性。

1.通过Tag的名字来获得Tag

print(soup.head)
print(soup.title)

<head><title>The Dormouse's story</title></head>
<title>The Dormouse's story</title>

通过名字的方法只能获得第一个Tag，如果要获得所有的某种Tag可以使用find_all方法

soup.find_all('a')

[<a class="sister" href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link1">Elsie</a>,
<a class="sister" href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link2">Lacie</a>,
<a class="sister" href="http://example.com/tillie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link3">Tillie</a>]

2.contents属性：将Tag的子节点通过列表的方式返回

head_tag = soup.head
head_tag.contents

[<title>The Dormouse's story</title>]

title_tag = head_tag.contents[0]
title_tag

<title>The Dormouse's story</title>

title_tag.contents

["The Dormouse's story"]

3.children：通过该属性对子节点进行循环

for child in title_tag.children:
print(child)

The Dormouse's story

4.descendants：不论是contents还是children都是返回直接子节点，而descendants对所有tag的子孙节点进行递归循环

for child in head_tag.children:
print(child)

<title>The Dormouse's story</title>

for child in head_tag.descendants:
print(child)

<title>The Dormouse's story</title>
The Dormouse's story

5.string 如果tag只有一个NavigableString类型的子节点，那么tag可以使用.string得到该子节点

title_tag.string

"The Dormouse's story"

如果一个tag只有一个子节点，那么使用.string可以获得其唯一子结点的NavigableString.

head_tag.string

"The Dormouse's story"

如果tag有多个子节点，tag无法确定.string对应的是那个子结点的内容，故返回None

print(soup.html.string)

None

6.strings和stripped_strings

如果tag包含多个字符串，可以使用.strings循环获取

for string in soup.strings:
print(string)

The Dormouse's story
The Dormouse's story
Once upon a time there were three little sisters; and their names were
Elsie
,
Lacie
and
Tillie
;
and they lived at the bottom of a well.
...

.string输出的内容包含了许多空格和空行，使用strpped_strings去除这些空白内容

for string in soup.stripped_strings:
print(string)

The Dormouse's story
The Dormouse's story
Once upon a time there were three little sisters; and their names were
Elsie
,
Lacie
and
Tillie
;
and they lived at the bottom of a well.
...

二、父节点

1.parent：获得某个元素的父节点

title_tag = soup.title
title_tag.parent

<head><title>The Dormouse's story</title></head>

字符串也有父节点

title_tag.string.parent

<title>The Dormouse's story</title>

2.parents：递归的获得所有父辈节点

link = soup.a
for parent in link.parents:
if parent is None:
print(parent)
else:
print(parent.name)

p
body
html
[document]

三、兄弟结点

sibling_soup = BeautifulSoup("<a>text1<c>text2</c></a>",'lxml')
print(sibling_soup.prettify())

<html>
<body>
<a>
text1
<c>
text2
</c>
</a>
</body>
</html>

1.next_sibling和previous_sibling

sibling_soup.b.next_sibling

<c>text2</c>

sibling_soup.c.previous_sibling

text1

在实际文档中.next_sibling和previous_sibling通常是字符串或者空白符

soup.find_all('a')

[<a class="sister" href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link1">Elsie</a>,
<a class="sister" href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link2">Lacie</a>,
<a class="sister" href="http://example.com/tillie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link3">Tillie</a>]

soup.a.next_sibling # 第一个<a></a>的next_sibling是,\n

',\n'

soup.a.next_sibling.next_sibling

<a class="sister" href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link2">Lacie</a>

2.next_siblings和previous_siblings

for sibling in soup.a.next_siblings:
print(repr(sibling))

',\n'
<a class="sister" href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link2">Lacie</a>
' and\n'
<a class="sister" href="http://example.com/tillie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link3">Tillie</a>
';\nand they lived at the bottom of a well.'

for sibling in soup.find(id="link3").previous_siblings:
print(repr(sibling))

' and\n'
<a class="sister" href="http://example.com/lacie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link2">Lacie</a>
',\n'
<a class="sister" href="http://example.com/elsie" rel="external nofollow" rel="external nofollow" rel="external nofollow" rel="external nofollow" id="link1">Elsie</a>
'Once upon a time there were three little sisters; and their names were\n'

四、回退与前进

1.next_element和previous_element

指向下一个或者前一个被解析的对象(字符串或tag)，即深度优先遍历的后序节点和前序节点