时间:2020-10-06来源:www.pcxitongcheng.com作者:电脑系统城
1. 引入头文件
?1 | #include <tuple> |
2. std::tuple初始化
?1 | std::tuple< int , std::string, float > t1(10, "Test" , 3.14); |
这里要注意,不是所有的C++ 11编译器都支持copy-list-initialization的方式。如下代码所示。
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std::tuple< int , int > foo_tuple() { return {1, -1}; // Error until N4387 return std::tuple< int , int >{1, -1}; // Always works return std::make_tuple(1, -1); // Always works } |
3. 打印std::tuple
打印std::tuple可以将它的元素逐个打印出来,不过非常繁琐,我们可以通过如下通用的打印函数,帮助我们一次性的将tuple的所有要素打印出来。
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#include <iostream> #include <tuple> #include <string> // helper function to print a tuple of any size template < class Tuple, std:: size_t N> struct TuplePrinter { static void print( const Tuple& t) { TuplePrinter<Tuple, N-1>::print(t); std::cout << ", " << std::get<N-1>(t); } }; template < class Tuple> struct TuplePrinter<Tuple, 1> { static void print( const Tuple& t) { std::cout << std::get<0>(t); } }; template < typename ... Args, std::enable_if_t< sizeof ...(Args) == 0, int > = 0> void print( const std::tuple<Args...>& t) { std::cout << "()\n" ; } template < typename ... Args, std::enable_if_t< sizeof ...(Args) != 0, int > = 0> void print( const std::tuple<Args...>& t) { std::cout << "(" ; TuplePrinter<decltype(t), sizeof ...(Args)>::print(t); std::cout << ")\n" ; } // end helper function int main() { std::tuple< int , std::string, float > t1(10, "Test" , 3.14); print(t1); } |
输出:
(10, Test, 3.14)
4、合并多个std::tuple
std::tuple_cat函数可以将多个std::tuple合并为一个tuple。
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int main() { std::tuple< int , std::string, float > t1(10, "Test" , 3.14); int n = 7; auto t2 = std::tuple_cat(t1, std::make_tuple( "Foo" , "bar" ), t1, std::tie(n)); n = 42; print(t2); } |
输出:
(10, Test, 3.14, Foo, bar, 10, Test, 3.14, 42)
5. std::tuple的解包(unpack)
std::tie能够将std::tuple包含的要素解包(unpack)成单个的对象。
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#include <iostream> #include <tuple> #include <string> int main() { auto info = std::make_tuple(3.8, 'A' , "Lisa Simpson" ); double score = 0.0; char grade; std::string name; std::tie(score, grade, name) = info; std::cout << "score:" << score << ", grade:" << grade << ", name:" << name << std::endl; return 0; } |
输出:
score:3.8, grade:A, name:Lisa Simpson
std::tie还支持std::pair对象的解包(unpack)。
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#include <iostream> #include <tuple> #include <string> #include <utility> int main() { auto info = std::make_pair(3.8, "Lisa Simpson" ); double score = 0.0; std::string name; std::tie(score, name) = info; std::cout << "score:" << score << ", name:" << name << std::endl; return 0; } |
输出:
score:3.8, name:Lisa Simpson
当我们不关注tuple中的某个元素时,可以使用std::ignore忽略该元素。
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#include <iostream> #include <tuple> #include <string> #include <utility> int main() { auto info = std::make_pair(3.8, "Lisa Simpson" ); double score = 0.0; std::string name; std::tie(score, std::ignore) = info; std::cout << "score:" << score << ", name:" << name << std::endl; return 0; } |
输出:
score:3.8, name:
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